Mathematics · 2020
JEE Main · 2 September 2020, Shift 2 · Q57
If the sum of first 11 terms of an A.P., a_1, a_2, a_3, … is 0( a_1 ≠ 0), then the sum of the A.P., a_1, a_3, a_5, …, a_23 is ka_1, where k is equal…
If the sum of first $\displaystyle 11$ terms of an A.P., $\displaystyle \mathrm{a}_1$, $\displaystyle \mathrm{a}_2, \mathrm{a}_3, \ldots$ is $\displaystyle 0\left(\mathrm{a}_1 \neq 0\right)$, then the sum of the A.P., $\displaystyle \mathrm{a}_1, \mathrm{a}_3, \mathrm{a}_5, \ldots, \mathrm{a}_{23}$ is $\displaystyle \mathrm{ka}_1$, where k is equal to :
Official answer
(4)
$\displaystyle -\frac{72}{5}$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.