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Mathematics · 2026

JEE Main · 23 January 2026, Shift 2 · Q25

If the solution curve y=f(x) of the differential equation (x^2-4) y^′-2 x y+2 x(4-x^2)^2=0, x>2, passes through the point (3,15), then the local…

If the solution curve $\displaystyle y=f(x)$ of the differential equation $\displaystyle \left(x^2-4\right) y^{\prime}-2 x y+2 x\left(4-x^2\right)^2=0, x>2$, passes through the point $\displaystyle (3,15)$, then the local maximum value of $\displaystyle f$ is $\displaystyle \_\_\_\_$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.