Mathematics · 2021
JEE Main · 25 February 2021, Shift 2 · Q87
If the remainder when x is divided by 4 is 3, then the remainder when (2020+x)^2022 is divided by 8 is \ \ \ \.
If the remainder when $\displaystyle x$ is divided by $\displaystyle 4$ is $\displaystyle 3$ , then the remainder when $\displaystyle (2020+x)^{2022}$ is divided by $\displaystyle 8$ is \_\_\_\_.
Official answer
1
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.