Mathematics · 2021
JEE Main · 31 August 2021, Shift 2 · Q87
If the line y= m x bisects the area enclosed by the lines x=0, y=0, x=3/2 and the curve y=1+4 x-x^2, then 12 m is equal to \ \ \ \.
If the line $\displaystyle y=\mathrm{m} x$ bisects the area enclosed by the lines $\displaystyle x=0, y=0, x=\frac{3}{2}$ and the curve $\displaystyle y=1+4 x-x^2$, then $\displaystyle 12$ m is equal to \_\_\_\_.
Official answer
26
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.