Mathematics · 2026
JEE Main · 24 January 2026, Shift 1 · Q17
If the function f(x)=(e^x(e^tan x-x-1)+ log_e( sec x+ tan x)-x)/(tan x-x) is continuous at x=0, then the value of f(0) is equal to
If the function $\displaystyle f(x)=\frac{e^x\left(e^{\tan x-x}-1\right)+\log _e(\sec x+\tan x)-x}{\tan x-x}$ is continuous at $\displaystyle x=0$, then the value of $\displaystyle f(0)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \frac{3}{2}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.