If lim_x → 2 (sin (x^3-5 x^2+ a x+ b ))/((√(x-1)-1) log_e (x-1))= m, then a + b + m is equal to:

If $\displaystyle \lim _{x \rightarrow 2} \frac{\sin \left(x^3-5 x^2+\mathrm{a} x+\mathrm{b}\right)}{(\sqrt{x-1}-1) \log _{\mathrm{e}}(x-1)}=\mathrm{m}$, then $\displaystyle \mathrm{a}+\mathrm{b}+\mathrm{m}$ is equal to :