Mathematics · 2019
JEE Main · 8 April 2019, Shift 2 · Q67
If the fourth term in the binomial expansion of (√(1/(x^1+ log_10 x))+x^(1/12))^6 is equal to 200, and x>1, then the value of x is:
If the fourth term in the binomial expansion of $\displaystyle \left(\sqrt{\frac{1}{x^{1+\log _{10} x}}}+x^{\frac{1}{12}}\right)^6$ is equal to $\displaystyle 200$, and $\displaystyle x>1$, then the value of $\displaystyle x$ is :
Official answer
No correct option: NTA dropped this question in its final answer key.
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.