If the foci of a hyperbola are same as that of the ellipse x^2/9+y^2/25=1 and the eccentricity of the hyperbola is 15/8 times the eccentricity of the…

If the foci of a hyperbola are same as that of the ellipse $\displaystyle \frac{x^2}{9}+\frac{y^2}{25}=1$ and the eccentricity of the hyperbola is $\displaystyle \frac{15}{8}$ times the eccentricity of the ellipse, then the smaller focal distance of the point $\displaystyle \left(\sqrt{2}, \frac{14}{3} \sqrt{\frac{2}{5}}\right)$ on the hyperbola, is equal to