Mathematics · 2023
JEE Main · 29 January 2023, Shift 2 · Q87
If the equation of the normal to the curve y=(x-a)/((x+b)(x-2)) at the point (1,-3) is x-4 y=13, then the value of a+b is equal to ____.
If the equation of the normal to the curve $\displaystyle y=\frac{x-a}{(x+b)(x-2)}$ at the point $\displaystyle (1,-3)$ is $\displaystyle x-4 y=13$, then the value of $\displaystyle a+b$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
4
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.