Mathematics · 2025
JEE Main · 3 April 2025, Shift 2 · Q23
If the equation of the hyperbola with foci (4,2) and (8,2) is 3 x^2-y^2-α x+β y+γ=0, then α+β+γ is equal to ____.
If the equation of the hyperbola with foci $\displaystyle (4,2)$ and $\displaystyle (8,2)$ is $\displaystyle 3 x^2-y^2-\alpha x+\beta y+\gamma=0$, then $\displaystyle \alpha+\beta+\gamma$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
141
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.