Mathematics · 2019
JEE Main · 12 April 2019, Shift 1 · Q76
If the area (in sq. units) of the region {(x, y): y^2 ≤ 4 x, x+y ≤ 1, x ≥ 0, y ≥ 0} is a √ 2 + b, then a - b is equal to:
If the area (in sq. units) of the region $\displaystyle \left\{(x, y): y^2 \leq 4 x, x+y \leq 1, x \geqslant 0, y \geqslant 0\right\}$ is $\displaystyle \mathrm{a} \sqrt{2}+\mathrm{b}$, then $\displaystyle \mathrm{a}-\mathrm{b}$ is equal to:
Official answer
(2)
$\displaystyle 6$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.