Mathematics · 2021
JEE Main · 3 August 2021, Shift 2 · Q85
If the area (in sq. units) bounded by the parabolas 5 x^2-y=0 and 2 x^2-y+b=0(b>0) is 12 √ 3, then ' b ' is equal to \ \ \ \.
If the area (in sq. units) bounded by the parabolas $\displaystyle 5 x^2-y=0$ and $\displaystyle 2 x^2-y+b=0(b>0)$ is $\displaystyle 12 \sqrt{3}$, then ' $\displaystyle b$ ' is equal to \_\_\_\_.
Official answer
9
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