If the angle made by the tangent at the point (x_0, y_0) on the curve x=12(t+ sin t cos t), y=12(1+ sin t)^2, 0<t<(π)/2, with the positive x -axis is…

If the angle made by the tangent at the point $\displaystyle \left(x_0, y_0\right)$ on the curve $$x=12(t+\sin t \cos t), $$ $\displaystyle y=12(1+\sin t)^2, 0<t<\frac{\pi}{2}$, with the positive $\displaystyle x$-axis is $\displaystyle \frac{\pi}{3}$, then $\displaystyle y_0$ is equal to: