Mathematics · 2026
JEE Main · 22 January 2026, Shift 2 · Q20
If y=y(x) satisfies the differential equation 16(√(x+9 √ x))(4+√(9+√ x)) cos y d y=(1+2 sin y) d x, x>0 and y(256)=(π)/2, y(49)=α, then 2 sin α is…
If $\displaystyle y=y(x)$ satisfies the differential equation
$\displaystyle 16(\sqrt{x+9 \sqrt{x}})(4+\sqrt{9+\sqrt{x}}) \cos y \mathrm{~d} y=(1+2 \sin y) \mathrm{d} x, x>0$ and $\displaystyle y(256)=\frac{\pi}{2}, y(49)=\alpha$, then $\displaystyle 2 \sin \alpha$ is equal to :
Official answer
From NTA’s final answer key for this paper.
No correct option: NTA dropped this question in its final answer key.
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.