Mathematics · 2019
JEE Main · 11 January 2019, Shift 1 · Q62
If one real root of the quadratic equation 81 x^2+ k x+256=0 is cube of the other root, then a value of k is:
If one real root of the quadratic equation $\displaystyle 81 x^2+\mathrm{k} x+256=0$ is cube of the other root, then a value of $\displaystyle k$ is :
Official answer
(1)
$\displaystyle -300$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.