If in the expansion of (1+x)^p (1-x)^q, the coefficients of x and x^2 are 1 and -2, respectively, then p^2+ q^2 is equal to:

If in the expansion of $\displaystyle (1+x)^{\mathrm{p}}(1-x)^{\mathrm{q}}$, the coefficients of $\displaystyle x$ and $\displaystyle x^2$ are $\displaystyle 1$ and -$\displaystyle 2$, respectively, then $\displaystyle \mathrm{p}^2+\mathrm{q}^2$ is equal to :