Mathematics · 2019
JEE Main · 12 January 2019, Shift 1 · Q63
If λ be the ratio of the roots of the quadratic equation in x, 3 m^2 x^2+ m ( m -4) x+2=0, then the least value of m for which λ+1/(λ)=1, is:
If $\displaystyle \lambda$ be the ratio of the roots of the quadratic equation in $\displaystyle x, 3 \mathrm{~m}^2 x^2+\mathrm{m}(\mathrm{m}-4) x+2=0$, then the least value of m for which
$\displaystyle \lambda+\frac{1}{\lambda}=1$, is :
Official answer
(1)
$\displaystyle 4-3 \sqrt{2}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.