Mathematics · 2018
JEE Main · 15 April 2018, Shift 2 · Q74
If ∫ (2 x+5)/(√(7-6 x-x^2)) d x= A √(7-6 x-x^2)+ B sin^-1((x+3)/4)+ C (where C is a constant of integration), then the ordered pair (A, B) is equal…
If $\displaystyle \int \frac{2 x+5}{\sqrt{7-6 x-x^2}} \mathrm{~d} x=\mathrm{A} \sqrt{7-6 x-x^2}+$
B $\displaystyle \sin ^{-1}\left(\frac{x+3}{4}\right)+\mathrm{C}$
(where C is a constant of integration), then the ordered pair (A, B) is equal to :
Official answer
(2)
$\displaystyle (-2, -1)$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.