Mathematics · 2021
JEE Main · 18 March 2021, Shift 1 · Q83
If f(x)=∫ (5 x^8+7 x^6)/((x^2+1+2 x^7)^2) d x,(x ≥ 0), f(0)=0 and f(1)=1/K, then the value of K is \ \ \ \.
If $\displaystyle f(x)=\int \frac{5 x^8+7 x^6}{\left(x^2+1+2 x^7\right)^2} \mathrm{~d} x,(x \geqslant 0), f(0)=0$ and $\displaystyle f(1)=\frac{1}{\mathrm{~K}}$, then the value of K is
\_\_\_\_.
Official answer
4
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.