Mathematics · 2020
JEE Main · 9 January 2020, Shift 2 · Q71
If C_r ≡^25 C_r and C_0+5 · C_1+9 · C_2+…..+(101) · C_25=2^25 · k, then k is equal to \ \ \ \.
If $\displaystyle \mathrm{C}_{\mathrm{r}} \equiv{ }^{25} \mathrm{C}_{\mathrm{r}}$ and
$$C_0+5 \cdot C_1+9 \cdot C_2+\ldots . .+(101) \cdot C_{25}=2^{25} \cdot \mathrm{k},
$$
then k is equal to \_\_\_\_.
Official answer
51
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.