Mathematics · 2026
JEE Main · 28 January 2026, Shift 1 · Q2
If g(x)=3 x^2+2 x-3, f(0)=-3 and 4 g(f(x))=3 x^2-32 x+72, then f(g(2)) is equal to:
If $\displaystyle g(x)=3 x^2+2 x-3, f(0)=-3$ and $\displaystyle 4 g(f(x))=3 x^2-32 x+72$, then $\displaystyle f(g(2))$ is equal to:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{7}{2}$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.