SolveItJEE Main
Mathematics · 2026

JEE Main · 6 April 2026, Shift 2 · Q1

Let f: R → R be defined as f(x)=(2 x^2-3 x+2)/(3 x^2+x+3). Then f is:

Let $\displaystyle f: \mathbf{R} \rightarrow \mathbf{R}$ be defined as $\displaystyle f(x)=\frac{2 x^2-3 x+2}{3 x^2+x+3}$. Then $\displaystyle f$ is :
ShareWhatsAppTelegram

More from Relations and Functions

JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.