Mathematics · 2024
JEE Main · 1 February 2024, Shift 1 · Q20
If tan A =1/(√(x(x^2+x+1))), tan B =(√ x)/(√(x^2+x+1)) and tan C =(x^-3+x^-2+x^-1)^1 / 2, 0< A, B, C <(π)/2, then A + B is equal to:
If $\displaystyle \tan \mathrm{A}=\frac{1}{\sqrt{x\left(x^2+x+1\right)}}, \tan \mathrm{B}=\frac{\sqrt{x}}{\sqrt{x^2+x+1}}$ and $\displaystyle \tan \mathrm{C}=\left(x^{-3}+x^{-2}+x^{-1}\right)^{1 / 2}, 0<\mathrm{A}, \mathrm{B}, \mathrm{C}<\frac{\pi}{2}$, then $\displaystyle \mathrm{A}+\mathrm{B}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(1)
C
More from Trigonometric Identities
- Let (π)/2<θ<π and cot θ=-1/(2 √2). Then the value of sin ((15 θ)/2)( cos 8 θ+ sin 8 θ)+ cos ((15 θ)/2)( cos 8 θ- sin 8 θ) is equal to2026
- If (cos^2 48^°- sin^2 12^°)/(sin^2 24^°- sin^2 6^°)=(α+β √5)/2, where α, β ∈ N, then α+β is equal to ____2026
- Let tan A, tan B, where A, B ∈(-(π)/2, (π)/2), be the roots of the quadratic equation x^2-2 x-5=0. Then 20 sin^2((A+B)/2) is equal to:2026
- For the functions f(θ)=α tan^2 θ+β cot^2 θ, and g(θ)=α sin^2 θ+β cos^2 θ, α>β>0, let min_0<θ<(π)/2 f(θ)= max_0<θ<π g(θ). If the first term of a G.P.…2026
- Let cos (α+β)=-1/10 and sin (α-β)=3/8, where 0<α<(π)/3 and 0<β<(π)/4. If tan 2 α=(3(1-r √5))/(√11(s+√5)), r, s ∈ N, then r+s is equal to ____.2026
- Let the range of the function f(x)=6+16 cos x · cos ((π)/3-x) · cos ((π)/3+x) · sin 3 x · cos 6 x, x ∈ R be [α, β]. Then the distance of the point…2025
- The value of ( sin 70^°)( cot 10^° cot 70^°-1) is2025
- The value of cosec 10^°-√3 sec 10^° is equal to:2026
JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.