If α and β are the roots of the quadratic equation, x^2+x sin θ-2 sin θ=0, θ ∈(0, (π)/2), then (α^12+β^12)/((α^-12+β^-12) ·(α-β)^24) is equal to:

If $\displaystyle \alpha$ and $\displaystyle \beta$ are the roots of the quadratic equation, $\displaystyle x^2+x \sin \theta-2 \sin \theta=0, \theta \in\left(0, \frac{\pi}{2}\right)$, then $\displaystyle \frac{\alpha^{12}+\beta^{12}}{\left(\alpha^{-12}+\beta^{-12}\right) \cdot(\alpha-\beta)^{24}}$ is equal to :