Mathematics · 2013
JEE Main · 25 April 2013, Shift 1 · Q88
If an equation of a tangent to the curve, y= cos (x+y),-1 ≤ x ≤ 1+π, is x+2 y=k then k is equal to:
If an equation of a tangent to the curve, $\displaystyle y=\cos (x+y),-1 \leq x \leq 1+\pi$, is $\displaystyle x+2 y=k$ then $\displaystyle k$ is equal to :
Official answer
(4)
$\displaystyle \frac{\pi}{2}$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.