Mathematics · 2018
JEE Main · 15 April 2018, Shift 2 · Q68
If a, b, c are in A.P. and a ^2, b^2, c^2 are in G.P. such that a < b < c and a + b + c =3/4, then the value of a is:
If a, b, c are in A.P. and a $\displaystyle { }^2, \mathrm{~b}^2, \mathrm{c}^2$ are in G.P. such that $\displaystyle \mathrm{a}<\mathrm{b}<\mathrm{c}$ and $\displaystyle \mathrm{a}+\mathrm{b}+\mathrm{c}=\frac{3}{4}$, then the value of a is :
Official answer
(3)
$\displaystyle \frac{1}{4}-\frac{1}{2 \sqrt{2}}$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.