Mathematics · 2024
JEE Main · 5 April 2024, Shift 2 · Q8
For x ≥ 0, the least value of K, for which 4^1+x+4^1-x, K/2, 16^x+16^-x are three consecutive terms of an A.P., is equal to:
For $\displaystyle x \geqslant 0$, the least value of $\displaystyle K$, for which $\displaystyle 4^{1+x}+4^{1-x}, \frac{K}{2}, 16^x+16^{-x}$ are three consecutive terms of an A.P., is equal to:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 10$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.