Mathematics · 2025
JEE Main · 7 April 2025, Shift 2 · Q23
For t >-1, let α_t and β_t be the roots of the equation (( t +2)^1 / 7-1) x^2+(( t +2)^1 / 6-1) x+(( t +2)^1 / 21-1)=0. If lim_t →-1^+ α_t = a and…
For $\displaystyle \mathrm{t}>-1$, let $\displaystyle \alpha_{\mathrm{t}}$ and $\displaystyle \beta_{\mathrm{t}}$ be the roots of the equation
$\displaystyle \left((\mathrm{t}+2)^{1 / 7}-1\right) x^2+\left((\mathrm{t}+2)^{1 / 6}-1\right) x+\left((\mathrm{t}+2)^{1 / 21}-1\right)=0$. If $\displaystyle \lim _{\mathrm{t} \rightarrow-1^{+}} \alpha_{\mathrm{t}}=\mathrm{a}$ and $\displaystyle \lim _{\mathrm{t} \rightarrow-1^{+}} \beta_{\mathrm{t}}=\mathrm{b}$, then $\displaystyle 72(a+b)^2$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
98
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.