Mathematics · 2021
JEE Main · 26 February 2021, Shift 2 · Q80
For x>0, if f(x)=∫_1^x (log_e t)/((1+ t )) dt, then f( e )+f(1/e) is equal to:
For $\displaystyle x>0$, if $\displaystyle f(x)=\int_1^x \frac{\log _{\mathrm{e}} \mathrm{t}}{(1+\mathrm{t})} \mathrm{dt}$, then $\displaystyle f(\mathrm{e})+f\left(\frac{1}{\mathrm{e}}\right)$ is equal to:
Official answer
(3)
$\displaystyle \frac{1}{2}$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.