Mathematics · 2023
JEE Main · 11 April 2023, Shift 2 · Q23
For k ∈ N, if the sum of the series 1+4/k+8/k^2+13/k^3+19/k^4+… is 10, then the value of k is ____
For $\displaystyle k \in \mathbb{N}$, if the sum of the series $\displaystyle 1+\frac{4}{k}+\frac{8}{k^2}+\frac{13}{k^3}+\frac{19}{k^4}+\ldots$ is $\displaystyle 10$ , then the value of $\displaystyle k$ is $\displaystyle \_\_\_\_$
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From NTA’s final answer key for this paper.
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.