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Mathematics · 2024

JEE Main · 29 January 2024, Shift 1 · Q12

For x ∈(-(π)/2, (π)/2), if y(x)=∫ (cosec x+ sin x)/(cosec x sec x+ tan x sin^2 x) d x, and lim_x →((π)/2)^- y(x)=0 then y((π)/4) is equal to

For $\displaystyle x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$, if $\displaystyle y(x)=\int \frac{\operatorname{cosec} x+\sin x}{\operatorname{cosec} x \sec x+\tan x \sin ^2 x} d x$, and $\displaystyle \lim _{x \rightarrow\left(\frac{\pi}{2}\right)^{-}} y(x)=0$ then $\displaystyle y\left(\frac{\pi}{4}\right)$ is equal to
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.