Mathematics · 2024
JEE Main · 29 January 2024, Shift 1 · Q12
For x ∈(-(π)/2, (π)/2), if y(x)=∫ (cosec x+ sin x)/(cosec x sec x+ tan x sin^2 x) d x, and lim_x →((π)/2)^- y(x)=0 then y((π)/4) is equal to
For $\displaystyle x \in\left(-\frac{\pi}{2}, \frac{\pi}{2}\right)$, if $\displaystyle y(x)=\int \frac{\operatorname{cosec} x+\sin x}{\operatorname{cosec} x \sec x+\tan x \sin ^2 x} d x$, and $\displaystyle \lim _{x \rightarrow\left(\frac{\pi}{2}\right)^{-}} y(x)=0$ then $\displaystyle y\left(\frac{\pi}{4}\right)$ is equal to
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{1}{\sqrt{2}} \tan ^{-1}\left(-\frac{1}{2}\right)$
More from Indefinite Integration
- The integral ∫ ((x^8-x^2) d x)/((x^12+3 x^6+1) tan^-1(x^3+1/x^3)) is equal to:2024
- If ∫((1-5 cos^2 x)/(sin^5 x cos^2 x)) d x=f(x)+C, where C is the constant of integration, then f((π)/6)-f((π)/4) is equal to2026
- If ∫ e^x((x sin^-1 x)/(√(1-x^2))+(sin^-1 x)/((1-x^2)^3 / 2)+x/(1-x^2)) d x=g(x)+C, where C is the constant of integration, then g(1/2) equals:2025
- If ∫ cosec^5 x d x=α cot x cosec x(coesc^2 x+3/2)+β log_e| tan x/2|+C where α, β ∈ R and C is the constant of integration, then the value of 8(α+β)…2024
- If ∫ (2 x^2+5 x+9)/(√(x^2+x+1)) d x=x √(x^2+x+1)+α √(x^2+x+1)+β log_e|x+1/2+√(x^2+x+1)|+C, where C is the constant of integration, then α+2 β is…2025
- If f(x)=∫ 1/(x^1 / 4(1+x^1 / 4)) d x, f(0)=-6, then f(1) is equal to:2025
- Let ∫ x^3 sin x d x=g(x)+C, where C is the constant of integration. If 8(g((π)/2)+g^′((π)/2))=α π^3+β π^2+γ, α, β, γ ∈ Z, then α+β-γ equals:2025
- Let f(x)=∫ (d x)/(x^(2/3)+2 x^(1/2)) be such that f(0)=-26+24 log_e(2). If f(1)=a+b log_e(3), where a, b ∈ Z, then a+b is equal to:2026
JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.