Mathematics · 2019
JEE Main · 10 January 2019, Shift 1 · Q63
Consider the quadratic equation ( c -5) x^2-2 c x+( c -4)=0, c ≠ 5. Let S be the set of all integral values of c for which one root of the equation…
Consider the quadratic equation $\displaystyle (\mathrm{c}-5) x^2-2 \mathrm{c} x+(\mathrm{c}-4)=0, \mathrm{c} \neq 5$. Let S be the set of all integral values of c for which one root of the equation lies in the interval $\displaystyle (0,2)$ and its other root lies in the interval $\displaystyle (2,3)$. Then the number of elements in S is :
Official answer
(3)
$\displaystyle 11$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.