Mathematics · 2021
JEE Main · 16 March 2021, Shift 2 · Q74
Consider the integral I =∫_0^10 ([x] e^[x])/(e^x-1) d x, where [x] denotes the greatest integer less than or equal to x. Then the value of I is equal…
Consider the integral
$$\mathrm{I}=\int_0^{10} \frac{[x] \mathrm{e}^{[x]}}{\mathrm{e}^{x-1}} \mathrm{~d} x,
$$
where $\displaystyle [x]$ denotes the greatest integer less than or equal to $\displaystyle x$. Then the value of I is equal
to :
Official answer
(3)
$\displaystyle 45(e-1)$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.