Mathematics · 2023
JEE Main · 13 April 2023, Shift 1 · Q10
max_0 ≤ x ≤ π{x-2 sin x cos x+1/3 sin 3 x}=
$$\max _{0 \leq x \leq \pi}\left\{x-2 \sin x \cos x+\frac{1}{3} \sin 3 x\right\}=
$$
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{5 \pi+2+3 \sqrt{3}}{6}$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.