Mathematics · 2014
JEE Main · 11 April 2014, Shift 1 · Q66
An eight digit number divisible by 9 is to be formed using digits from 0 to 9 without repeating the digits. The number of ways in which this can be…
An eight digit number divisible by $\displaystyle 9$ is to be formed using digits from $\displaystyle 0$ to $\displaystyle 9$ without repeating the digits. The number of ways in which this can be done is :
Official answer
(4)
$\displaystyle 36$ ($\displaystyle 7$!)
More from Permutations and Combinations
- If all the six digit numbers x_1 x_2 x_3 x_4 x_5 x_6 with 0<x_1<x_2<x_3<x_4<x_5<x_6 are arranged in the increasing order, then the sum of the digits…2023
- The number of symmetric matrices of order 3, with all the entries from the set \{0, 1, 2, 3, 4, 5, 6, 7, 8, 9\}, is2023
- A scientific committee is to be formed from 6 Indians and 8 foreigners, which includes at least 2 Indians and double the number of foreigners as…2021
- The number of three-digit even numbers, formed by the digits 0,1,3,4,6,7 if the repetition of digits is not allowed, is \ \ \ \.2021
- Let A={x_1, x_2, …, x_7} and B={y_1, y_2, y_3} be two sets containing seven and three distinct elements respectively. Then the total number of…2015
- Two families with three members each and one family with four members are to be seated in a row. In how many ways can they be seated so that the same…2020
- The number of natural numbers, between 212 and 999, such that the sum of their digits is 15, is ____.2025
- The number of ways in which 21 identical apples can be distributed among three children such that each child gets at least 2 apples, is2024
JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.