Mathematics · 2015
JEE Main · 11 April 2015, Shift 1 · Q61
Let A ={x_1, x_2, …, x_7} and B ={y_1, y_2, y_3} be two sets containing seven and three distinct elements respectively. Then the total number of…
Let $\displaystyle \mathrm{A}=\left\{x_1, x_2, \ldots, x_7\right\}$ and $\displaystyle \mathrm{B}=\left\{y_1, y_2, y_3\right\}$ be two sets containing seven and three distinct elements respectively. Then the total number of functions $\displaystyle f: \mathrm{A} \rightarrow \mathrm{B}$ that are onto, if there exist exactly three elements $\displaystyle x$ in A such that $\displaystyle f(x)=y_2$, is equal to :
Official answer
(4)
$\displaystyle 14 .{ }^7 C_3$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.