Mathematics · 2013
JEE Main · 22 April 2013, Shift 1 · Q68
3/1^2+5/(1^2+2^2)+7/(1^2+2^2+3^2)+… upto 11 -terms is:
\section*{The sum}
$$\frac{3}{1^2}+\frac{5}{1^2+2^2}+\frac{7}{1^2+2^2+3^2}+\ldots \text { upto }
$$
$\displaystyle 11$ -terms is :
Official answer
(3)
$\displaystyle \frac{11}{2}$
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.