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Chemistry · 2025

JEE Main · 2 April 2025, Shift 2 · Q69

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass…

When a concentrated solution of sulphanilic acid and $\displaystyle 1$-naphthylamine is treated with nitrous acid ($\displaystyle 273$ K) and acidified with acetic acid, the mass (g) of $\displaystyle 0.1$ mole of product formed is : (Given molar mass in $\displaystyle \mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14, \mathrm{O}: 16, \mathrm{~S}: 32$ )
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JEE Main 2025 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.