Chemistry · 2024
JEE Main · 27 January 2024, Shift 2 · Q81
Volume of 3 M NaOH (formula weight 40 g mol^-1 ) which can be prepared from 84 g of NaOH is ____ × 10^-1 dm^3.
Volume of $\displaystyle 3$ M NaOH (formula weight $\displaystyle 40 \mathrm{~g} \mathrm{~mol}^{-1}$ ) which can be prepared from $\displaystyle 84$ g of NaOH is
$\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-1} \mathrm{dm}^3$.
Official answer
From NTA’s final answer key for this paper.
7
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JEE Main 2024 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.