Chemistry · 2019
JEE Main · 8 April 2019, Shift 1 · Q56
The vapour pressures of pure liquids A and B are 400 and 600 mmHg, respectively at 298 K. On mixing the two liquids, the sum of their initial volumes…
The vapour pressures of pure liquids A and B are $\displaystyle 400$ and $\displaystyle 600$ mmHg , respectively at $\displaystyle 298$ K. On mixing the two liquids, the sum of their initial volumes is equal to the volume of the final mixture. The mole fraction of liquid B is $\displaystyle 0.5$ in the mixture. The vapour pressure of the final solution, the mole fractions of components A and B in vapour phase, respectively are :
Official answer
(1)
$\displaystyle 500$ mmHg, $\displaystyle 0.4$, $\displaystyle 0.6$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.