Chemistry · 2026
JEE Main · 2 April 2026, Shift 2 · Q71
The surface of sodium metal is irradiated with radiation of wavelength x nm. The kinetic energy of ejected electrons is 2.8 × 10^-20 J. The work…
The surface of sodium metal is irradiated with radiation of wavelength $\displaystyle x \mathrm{~nm}$. The kinetic energy of ejected electrons is $\displaystyle 2.8 \times 10^{-20} \mathrm{~J}$. The work function of sodium is $\displaystyle 2.3$ eV. The value of $\displaystyle x$ is
$\displaystyle \_\_\_\_$ $\displaystyle \times 10^2 \mathrm{~nm}$. (Nearest integer)
(Given : $\displaystyle \mathrm{h}=6.6 \times 10^{-34} \mathrm{~J} \mathrm{~s} ; 1 \mathrm{eV}=1.6 \times 10^{-19} \mathrm{~J} ; \mathrm{c}=3.0 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}$ )
Official answer
From NTA’s final answer key for this paper.
5
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.