Chemistry · 2026
JEE Main · 6 April 2026, Shift 1 · Q52
If shortest wavelength of hydrogen atom in Lyman series is x, then longest wavelength in Balmer series of He^+ is:
If shortest wavelength of hydrogen atom in Lyman series is $\displaystyle x$, then longest wavelength in Balmer series of $\displaystyle \mathrm{He}^{+}$is:
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \frac{9 x}{5}$
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JEE Main 2026 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.