Chemistry · 2020
JEE Main · 4 September 2020, Shift 2 · Q31
The shortest wavelength of H atom in the Lyman series is λ_1. The longest wavelength in the Balmer series of He^+ is:
The shortest wavelength of H atom in the Lyman series is $\displaystyle \lambda_1$. The longest wavelength in the Balmer series of $\displaystyle \mathrm{He}^{+}$is :
Official answer
(3)
$\displaystyle \frac{9 \lambda_1}{5}$
More from Atomic Structure
- If the Thompson model of the atom was correct, then the result of Rutherford's gold foil experiment would have been:2021
- The energy required by electrons, present in the first Bohr orbit of hydrogen atom to be excited to second Bohr orbit is ____ J mol^-1. Given:…2026
- Ge ( Z=32 ) in its ground state electronic configuration has x completely filled orbitals with m_l=0. The value of x is \ \ \ \.2021
- The orbital having two radial as well as two angular nodes is:2021
- The energy of one mole of photons of radiation of frequency 2 × 10^12 Hz in J mol^-1 is ____. (Nearest integer) [ Given: h=6.626 × 10^-34 J s;…2023
- Consider the following spectral lines for atomic hydrogen: A. First line of Paschen series B. Second line of Balmer series C. Third line of Paschen…2026
- The wavelength of an electron of kinetic energy 4.50 × 10^-29 J is ____ × 10^-5 m. (Nearest integer) Given: mass of electron is 9 × 10^-31 kg, h=6.6…2023
- Based on Heisenberg's uncertainty principle, the uncertainty in the velocity of the electron to be found within an atomic nucleus of diameter 10^-15…2024
JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.