The ratio of mass percentage ( w / w ) of C: H in a hydrocarbon is 12: 1. It has two carbon atoms. The weight (in g ) of CO_2( g ) formed when 3.38 g…

The ratio of mass percentage ( $\displaystyle \mathrm{w} / \mathrm{w}$ ) of $\displaystyle \mathrm{C}: \mathrm{H}$ in a hydrocarbon is $\displaystyle 12: 1$. It has two carbon atoms. The weight (in g ) of $\displaystyle \mathrm{CO}_2(\mathrm{~g})$ formed when $\displaystyle 3.38$ g of this hydrocarbon is completely burnt in oxygen is : (Given : Molar mass in $\displaystyle \mathrm{g} \mathrm{mol}^{-1} \mathrm{C}: 12, \mathrm{H}: 1,, \mathrm{O}: 16$ )