The mass of iron converted into Fe_3 O_4 by the action of 18 g of steam is: (Given: Molar mass of H, O and Fe are 1, 16 and 56 g mol^-1 respectively)…

The mass of iron converted into $\displaystyle \mathrm{Fe}_3 \mathrm{O}_4$ by the action of $\displaystyle 18$ g of steam is : (Given : Molar mass of H, O and Fe are $\displaystyle 1$, $\displaystyle 16$ and $\displaystyle 56 \mathrm{~g} \mathrm{~mol}^{-1}$ respectively) Assume iron is present in excess :