The quantum number of four electrons are given below: I. n =4, l=2, m_l=-2, m_s =-1 / 2 II. n =3, l=2, m_l=1, m_s =+1 / 2 III. n =4, l=1, m_l=0, m_s…

The quantum number of four electrons are given below : I. $\displaystyle \mathrm{n}=4, l=2, \mathrm{~m}_l=-2, \mathrm{~m}_{\mathrm{s}}=-1 / 2$ II. $\displaystyle \mathrm{n}=3, l=2, \mathrm{~m}_l=1, \mathrm{~m}_{\mathrm{s}}=+1 / 2$ III. $\displaystyle \mathrm{n}=4, l=1, \mathrm{~m}_l=0, \mathrm{~m}_{\mathrm{s}}=+\frac{1}{2}$ IV. $\displaystyle \mathrm{n}=3, l=1, \mathrm{~m}_l=1, \mathrm{~m}_{\mathrm{s}}=-1 / 2$ The correct order of their increasing energies will be :