Chemistry · 2019
JEE Main · 10 April 2019, Shift 2 · Q51
The minimum amount of O_2( g ) consumed per gram of reactant is for the reaction: (Given atomic mass: Fe =56, O =16, Mg =24, P =31, C =12, H =1 )
The minimum amount of $\displaystyle \mathrm{O}_2(\mathrm{~g})$ consumed per gram of reactant is for the reaction :
(Given atomic mass : $\displaystyle \mathrm{Fe}=56, \mathrm{O}=16$, $\displaystyle \mathrm{Mg}=24, \mathrm{P}=31, \mathrm{C}=12, \mathrm{H}=1$ )
Official answer
(1)
$\displaystyle 4 \mathrm{Fe}(\mathrm{~s})+3 \mathrm{O}_2(\mathrm{~g}) \rightarrow 2 \mathrm{Fe}_2 \mathrm{O}_3(\mathrm{~s})$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.