Chemistry · 2021
JEE Main · 3 August 2021, Shift 2 · Q57
The inactivation process of virus is first order with respect to virus concentration and 2% of the virus was inactivated in the first one minute.…
The inactivation process of virus is first order with respect to virus concentration and $\displaystyle 2$% of the virus was inactivated in the first one minute. Time taken (in minutes) for the virus to become $\displaystyle 75 \%$ inactivated is \_\_\_\_. (Nearest integer)
[Use $\displaystyle \log _{10} 2=0.3010, \log _{10} 3=0.4771$ ]
Official answer
69
More from Chemical Kinetics
- For a chemical reaction A+B → Product, the order is 1 with respect to A and B. What is the value of x and y?2023
- [A] → [B] Reactant Product If formation of compound [B] follows the first order of kinetics and after 70 minutes the concentration of [A] was found…2022
- Pre-exponential factors of two different reactions of same order are identical. Let activation energy of first reaction exceeds the activation energy…2026
- A → B (first reaction); C → D (second reaction) Consider the above two first-order reactions. The rate constant for first reaction at 500 K is double…2026
- Correct statements regarding Arrhenius equation among the following are: A. Factor e^-E a / R T corresponds to fraction of molecules having kinetic…2026
- N_2 O_5(g) → 2 NO_2(g)+1/2 O_2(g) In the above first order reaction the initial concentration of N_2 O_5 is 2.40 × 10^-2 mol L^-1 at 318 K. The…2021
- The rate constant for a first order reaction is given by the following equation: ln k=33.24-(2.0 × 10^4 K)/T The Activation energy for the reaction…2022
- 2 NO( g)+Cl_2( g) ⇌ 2 NOCl( s) This reaction was studied at -10^° C and the following data was obtained [NO]_0 and [Cl_2]_0 are the initial…2021
JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.