Chemistry · 2019
JEE Main · 10 January 2019, Shift 2 · Q53
The ground state energy of hydrogen atom is -13.6 eV. The energy of second excited state of He^+ ion in eV is:
The ground state energy of hydrogen atom is -$\displaystyle 13.6$ eV. The energy of second excited state of $\displaystyle \mathrm{He}^{+}$ion in eV is :
Official answer
(4)
$\displaystyle -6.04$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.