Chemistry · 2021
JEE Main · 24 February 2021, Shift 2 · Q51
The formula of a gaseous hydrocarbon which requires 6 times of its own volume of O_2 for complete oxidation and produces 4 times its own volume of…
The formula of a gaseous hydrocarbon which requires $\displaystyle 6$ times of its own volume of $\displaystyle \mathrm{O}_2$ for complete oxidation and produces $\displaystyle 4$ times its own volume of $\displaystyle \mathrm{CO}_2$ is $\displaystyle \mathrm{C}_x \mathrm{H}_y$. The value of $\displaystyle y$ is
\_\_\_\_.
Official answer
8
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.